1. 程式人生 > >Fri Oct 31 18:00:00 UTC+0800 2008轉換為yyyy-mm-dd

Fri Oct 31 18:00:00 UTC+0800 2008轉換為yyyy-mm-dd

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這個其實網上有很多例子,都是直接用js在前端做了時間處理,我的處理也一樣,想要變成2008-3-31,就用下面的js直接可以處理
    function Todate(num) { //Fri Oct 31 18:00:00 UTC+0800 2008
        num = num + "";
        var date = "";
        var month = new Array();
        month["Jan"] = 1; month["Feb"] = 2; month["Mar"] = 3; month["Apr"] = 4; month["May"] = 5; month["Jun"] = 6;
        month["Jul"] = 7; month["Aug"] = 8; month["Sep"] = 9; month["Oct"] = 10; month["Nov"] = 11; month["Dec"] = 12;
        var week = new Array();
        week["Mon"] = "一"; week["Tue"] = "二"; week["Wed"] = "三"; week["Thu"] = "四"; week["Fri"] = "五"; week["Sat"] = "六"; week["Sun"] = "日";
        str = num.split(" ");
        date = str[5] + "-";
        date = date + month[str[1]] + "-" + str[2];//獲取到的年月日,要是想加上時分秒,就date = date + month[str[1]] + "-" + str[2]+ " " + str[3];
        return date;
    }

我正好做項目,時間要轉換成2008-03,我就直接加了個判斷

function spliceZero(param)
		{
		    if (param < 10) {
		    param = "0" + param;
		}
		    return param;
		} 


/**
* 下面給個完整的例子
*
**/


function Todate(num) { //Fri Oct 31 18:00:00 UTC+0800 2008
if(num!=""){
num = num + "";
var date = "";
var month = new Array();
month["Jan"] = 1; month["Feb"] = 2; month["Mar"] = 3; month["Apr"] = 4; month["May"] = 5; month["Jun"] = 6;
month["Jul"] = 7; month["Aug"] = 8; month["Sep"] = 9; month["Oct"] = 10; month["Nov"] = 11; month["Dec"] = 12;
str = num.split(" ");
date = str[5] + "-";
date = date + spliceZero(month[str[1]]);
return date;
}else{
return "";
}

}

function spliceZero(param)
{
if (param < 10) {
param = "0" + param;
}
return param;
}

 

Fri Oct 31 18:00:00 UTC+0800 2008轉換為yyyy-mm-dd