python實現簡單的循環購物車小功能
阿新 • • 發佈:2017-07-05
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python實現簡單的循環購物車小功能
# -*- coding: utf-8 -*- __author__ = ‘hujianli‘ shopping = [ ("iphone6s", 5000), ("book python", 81), ("iwach", 3200), ("電視機", 2200) ] def zero(name): if len(name) == 0: print("\033[31;1m您的輸入不能為空,清重新輸入~~\033[0m") exit() else: return TrueView Codedef crre(name): if int(name) not in range(len(shopping)): print("\033[31;1m您輸入了錯誤的序列號,請重新輸入~~\033[0m") exit() else: return True gongzi = input("請輸入您目前的工資:") if not gongzi.isdigit(): crre() elif len(gongzi) == 0: zero() else: gongzi = int(gongzi) print("=========================================") print("===要購買的列表清單如下: ") for i,j in enumerate(shopping): print(i, j[0], j[1]) shopping_cart = [] while True: choice = input("請輸入你要購買的商品,輸入q或者exit退出選擇回到購物車列表: ") if choice.isdigit(): zero(choice) crre(choice) choice= int(choice) goods = shopping[choice] if gongzi < int(goods[1]): gongzi -= goods[1] print("===您的工資余額不夠使用了,還差\033[1;31m{}\033[0m請努力掙錢===.".format(abs(gongzi))) else: print("您選購的商品:\033[1;32m %s \033[0m 已經加入到購物車.." % (goods[0])) shopping_cart.append(goods) gongzi -= goods[1] print("您的工資余額還剩下:\033[30;42m %s\033[0m"% (gongzi)) elif (choice == "q") or (choice == "exit"): break print(‘\033[30;42m你已購商品列表\033[0m‘.center(42,‘-‘)) for i,j in enumerate(shopping_cart): print("\033[1;32m" + str(i+1) + " " + str(j[0]) + " " + str(j[1]) + "\033[0m")
python實現簡單的循環購物車小功能