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C# /date(1498820611133+0800)/ 轉DateTime

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開發中經常遇到日期轉換問題,特別是做接口的時候,現在整理了下時間戳轉為C#格式時間的方法:

 /// <summary>
        /// 時間戳轉為C#格式時間
        /// </summary>
        /// <param name="timeStamp"></param>
        /// <returns></returns>
        public string GetTime(string timeStamp)
        {
            //處理字符串,截取括號內的數字
            var
strStamp = Regex.Matches(timeStamp, @"(?<=\()((?<gp>\()|(?<-gp>\))|[^()]+)*(?(gp)(?!))").Cast<Match>().Select(t => t.Value).ToArray()[0].ToString(); //處理字符串獲取+號前面的數字 var str = Convert.ToInt64(strStamp.Substring(0, strStamp.IndexOf("+"))); long
timeTricks = new DateTime(1970, 1, 1).Ticks + str * 10000 + TimeZone.CurrentTimeZone.GetUtcOffset(DateTime.Now).Hours * 3600 * (long)10000000; return new DateTime(timeTricks).ToString("yyyy-MM-dd HH:mm:ss"); } /// <summary> /// DateTime時間格式轉換為Unix時間戳格式 /// </summary>
/// <param name="time"></param> /// <returns></returns> public int ConvertDateTimeInt(System.DateTime time) { System.DateTime startTime = TimeZone.CurrentTimeZone.ToLocalTime(new System.DateTime(1970, 1, 1)); return (int)(time - startTime).TotalSeconds; }

C# \/date(1498820611133+0800)\/ 轉DateTime