Leetcode 二分查找 Search Insert Position

阿新 • • 發佈：2017-08-12

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本文為senlie原創，轉載請保留此地址：http://blog.csdn.net/zhengsenlie

Search Insert Position

Total Accepted: 14279 Total Submissions: 41575

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0

題意：輸出一個元素在一個已排序的數組中的位置，假設不存在輸出它應該插入的位置
思路：二分查找，假設找到就輸出位置。找不到就輸出它應該插入的位置
復雜度：時間O(log n)，空間O(1)

相關題目：

Search a 2D Matrix

class Solution {
public:
    int searchInsert(int A[], int n, int target) {
    	 
int s = 0, e = n , m ; //中間數，偶數個的時候取前一個
    	while(s < e){
    		m = s + (e - s) / 2;
    		if(A[m] == target) return m;
    		if(A[m] < target) s = m + 1;
    		if(A[m] > target) e = m;
    	}
    	if(A[m] > target) return m;
    	else return m + 1;
    }
};

Leetcode 二分查找 Search Insert Position

ret pac spl tom tails neu cor pub acc 本文為senlie原創，轉載請保留此地址：http://blog.csdn.net/zhengsenlie Search Insert Position Total

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Leetcode 二分查找 Search Insert Position

Search Insert Position

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