Codeforces 605A. Sorting Railway Cars
An infinitely long railway has a train consisting of n cars, numbered from 1 to n (the numbers of all the cars are distinct) and positioned in arbitrary order. David Blaine wants to sort the railway cars in the order of increasing numbers. In one move he can make one of the cars disappear from its place and teleport it either to the beginning of the train, or to the end of the train, at his desire. What is the minimum number of actions David Blaine needs to perform in order to sort the train?
The first line of the input contains integer n (1?≤?n?≤?100?000) — the number of cars in the train.
The second line contains n integers pi (1?≤?pi?≤?n, pi?≠?pj if i?≠?j) — the sequence of the numbers of the cars in the train.
OutputPrint a single integer — the minimum number of actions needed to sort the railway cars.
開一個pos數組記錄每個數的位置,求該數組裏的最長連續遞增子序列長度即可
#include <iostream> #include <algorithm> #include <cstring> using namespace std; int f[100005]; int a[100005],pos[100005] = {0},n; int main(){ // freopen("test.in","r",stdin); cin >> n; for (int i=1;i<=n;i++){ cin >> a[i]; pos[a[i]]View Code= i; } int res = 0,now = 0; // for (int i=1;i<=n;i++){ // cout << pos[i] << " "; // }cout << endl; for (int i=1;i<=n;i++){ if (pos[i] > pos[i-1]){ now ++; // cout << i << i-1 << now << res << endl; } else { res = max(now,res); now = 1; } } res = max(now,res); cout << n - res; }
Codeforces 605A. Sorting Railway Cars