Invert Binary Tree

阿新 • • 發佈：2017-09-07

ges 思路 self. logs log self object 簡單 obj

　　　　這是一道簡單題

　　題目：

　　　　技術分享

　　思路：

　　　　本來最開始我想用BFS但是感覺那樣有點復雜，後來就用了遞歸的方法，把他們轉換為每個節點的左右節點都交換

　　代碼：

class Solution(object):
    def invertTree(self, root):
        """
        :type root: TreeNode
        :rtype: TreeNode
        """
        if not root: return None
               
        root.left = self.invertTree(root.left)
        root.right  
= self.invertTree(root.right)
        
        root.left, root.right = root.right, root.left
        return root

Invert Binary Tree

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Invert Binary Tree

ges 思路 self. logs log self object 簡單 obj 　　　　這是一道簡單題　　題目：　　　　　　思路：　　　　本來最開始我想用BFS但是感覺那樣有點復雜，後來就用了遞歸的方法，把他們轉換為每個節點的左右節點都交換　　代碼：　　　　

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Invert Binary Tree

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