[leetcode] 1. Two Sum
阿新 • • 發佈:2017-09-15
example solution cau 簡單 應該 pub ecif span code
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1].
這應該是leetcode裏最簡單的題,簡單的循環。
以下是我的代碼:
class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { vector<int> re; for (int i = 0; i < nums.size() - 1; i++) { for (int j = nums.size() - 1; j > i; j--) {if (nums[i] + nums[j] == target) { re.push_back(i); re.push_back(j); return re; } } } return re; } };
[leetcode] 1. Two Sum