Given a list of 24-hour clock time points in "Hour:Minutes" format, find the minimum minutes difference between any two time points in the list.

Example 1:

Input: ["23:59","00:00"]
Output: 1

Note:

1. The number of time points in the given list is at least 2 and won‘t exceed 20000.
2. The input time is legal and ranges from 00:00 to 23:59.

題目含義：給定一定24格式的Hour:Minutes字符，找到任意兩個時間點的最小時間差

 1     public int findMinDifference(List<String> timePoints) {
 2         boolean[] minutes = new boolean[24 * 60];
 3         for (String time : timePoints) {
 4             String[] values = time.split(":");
 5             int minute = Integer.valueOf(values[0]) * 60 + Integer.valueOf(values[1]);
 
 6             if (minutes[minute]) return 0;
 7             minutes[minute] = true;
 8         }
 9         int min = Integer.MAX_VALUE, left = Integer.MAX_VALUE, right = Integer.MIN_VALUE;
10         int previous = 0;//上一個時間值
11         for (int i = 0; i < minutes.length; i++) {
12             if (!minutes[i]) continue
 
;
13             if (left != Integer.MAX_VALUE) {
14                 min = Math.min(min, i - previous);//min記錄了最小的時間差
15             }
16             left = Math.min(left, i);//具體零點最近的點
17             right = Math.max(right, i);//距離零點最遠的點
18             previous = i;
19         }
20         return Math.min(min, 24 * 60 - right + left);     
21     }

539. Minimum Time Difference