108. Convert Sorted Array to Binary Search Tree

阿新 • • 發佈：2017-10-30

order binary node arr where balance logs roo search

Given an array where elements are sorted in ascending order, convert it to a height balanced BST.

 1 class Solution {
 2     public TreeNode sortedArrayToBST(int[] nums) {
 3          return nums.length==0? null : ToBST(nums,0,nums.length-1);
 4         
 5         
 6     }
 7     public TreeNode ToBST(int 
[] nums,int lo,int hi) {
 8         if(lo>hi) return null;
 9          int mid = (lo+hi)/2;
10          TreeNode root = new TreeNode(nums[mid]);
11          root.left = ToBST(nums,lo,mid-1);
12          root.right = ToBST(nums,mid+1,hi);
13          
14         return root;
15         
16     }
17 }

[Leetcode]108. Convert Sorted Array to Binary Search Tree

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108. Convert Sorted Array to Binary Search Tree

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LeetCode 108. Convert Sorted Array to Binary Search Tree

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Difficulty Easy. Problem Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this probl

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題目連結：https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ 題目要求將排序陣列轉為平衡二叉搜尋樹，先說一下二叉搜尋樹（Binary search tree）的定義和特性（wikipedia）：

LeetCode 108.Convert Sorted Array to Binary Search Tree (將有序陣列轉換為二叉搜尋樹)

題目描述：將一個按照升序排列的有序陣列，轉換為一棵高度平衡二叉搜尋樹。本題中，一個高度平衡二叉樹是指一個二叉樹每個節點的左右兩個子樹的高度差的絕對值不超過 1。示例: 給定有序陣列: [-10,-3,0,5,9], 一個可能的答案是：[0,-3,9,-10,

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https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ 把有序陣列轉為二叉查詢樹，本質上就是對陣列做二分查詢，中間元素就是根；然後在對左右兩個分割槽迭代二分查詢。本題可以用遞迴函式來

LeetCode --- 108. Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 這道題的要求是將有序陣列轉化成高度平衡的二叉搜尋樹（BST）。由於陣列有序，因此相當於二叉搜尋樹的前序遍歷。

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[Leetcode 108]有序陣列轉二叉搜尋樹Convert Sorted Array to Binary Search Tree

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LeetCode 108. 將有序陣列轉換為二叉搜尋樹（Convert Sorted Array to Binary Search Tree）原題思路程式碼原題將一個按照升序排列的有序陣列，轉換為一棵高度平衡二叉搜尋樹。

[Leetcode] convert sorted array to binary search tree

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LeetCode-Easy刷題(23) Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 將有序陣列轉化為二分查詢樹

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Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 這道題是要將有序陣列轉為二叉搜尋樹，所謂二叉搜尋樹，是一種始終滿足左<根<右的特性，如果將二

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108. Convert Sorted Array to Binary Search Tree

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