Python學習之路:內置函數
阿新 • • 發佈:2017-12-05
函數 utf capi dict lte python學習 func blog .cn
print(all([0,15,3]))# all全部都是可叠代的元素時返回TRUE print(all([1,15,3])) print(any([1,15,3]))#any任意一個是可叠代的元素時返回TRUE print(any([])) print(ascii([1,2,"開掛"])) #轉換成ASCII碼 a = ascii([1,2,"開掛"]) print(type(a),[a]) print(bin(1))#數字十進制轉二進制 print(bin(2)) bin(8) print(bin(255)) a = bytes("abcde",encoding="utf-8") print(a) print(a.capitalize(),a) print(bool(0)) print(bool(1)) print(bool([1])) b = bytearray("abcde",encoding="utf-8") print(b[0]) b[1] = 100 print(b) print(callable([]))#後面加()都是可調用的(callable判斷是否可調用) chr(87) #參數必須是數字,轉換為ASCII碼中的字符 ord(‘a‘)#ASCII碼的位置 #字符創變成執行代碼 code ="for i in range(10):print(i)" c = compile(code,‘‘,‘exec‘) print(c) exec(code) dict()#生成一個默認字典 a = () print(dir(a)) #有什麽方法 eval() def sayhi(n): print(n) for i in range(n): print(i) sayhi(3) #(lambda n:print(n))(5) calc = lambda n:print(n) calc(5) res = filter(lambda n:n>5,range(10))#filter過濾,返回叠代器 for i in res: print(i) res = map(lambda n:n*n,range(10))#[i*2 for i in range(10)] res1 =[lambda i:i*2 for i in range(10)] for i in res: print(i) import functools res = functools.reduce(lambda x,y:x+y,range(10))#0+1+2+……+9 res1 = functools.reduce(lambda x,y:x*y,range(1,10)) print(res) print(res1) a = frozenset([1,2,4,333,4,2,12])#凍結集合,不可修改 print(globals())#獲取當前程序中的所有變量 print(hash(12333))#哈希算法 print(hash(‘alex‘))
內置函數說明可參見http://www.cnblogs.com/sesshoumaru/p/6140987.html
Python學習之路:內置函數