Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation.

(Recall that the number of set bits an integer has is the number of 1s present when written in binary. For example, 21 written in binary is 10101 which has 3 set bits. Also, 1 is not a prime.)

Example 1:

Input: L = 6, R = 10
Output: 4
Explanation:
6 -> 110 (2 set bits, 2 is prime)
7 -> 111 (3 set bits, 3 is prime)
9 -> 1001 (2 set bits , 2 is prime)
10->1010 (2 set bits , 2 is prime)

Example 2:

Input: L = 10, R = 15
Output: 5
Explanation:
10 -> 1010 (2 set bits, 2 is prime)
11 -> 1011 (3 set bits, 3 is prime)
12 -> 1100 (2 set bits, 2 is prime)
13 -> 1101 (3 set bits, 3 is prime)
14 -> 1110 (3 set bits, 3 is prime)
15 -> 1111 (4 set bits, 4 is not prime)

Note:

1. L, R will be integers L <= R in the range [1, 10^6].
2. R - L will be at most 10000.

/**
 * @param {number} L
 * @param {number} R
 * @return {number}
 */
var countPrimeSetBits = function (L, R)
 
 {
    let primes = new Set([2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31]);
    let res = 0;
    while (L <= R) {
        let str = L.toString(2);
        let match = str.match(/1/g);
        if (match && primes.has(match.length)) {
            res++;
        }
        L++;
    }
    return res;
};
let res = countPrimeSetBits(10, 15);
console.log(res);

762. Prime Number of Set Bits in Binary Representation 二進制表示形式中的素數位數