sql語句：
1.Select COUNT(distinct ann_id) from dmdb.t_bond_ann_att_info where last_update_time >= ‘2018-03-09 14:00:00‘;

2.Select COUNT(id) from dmdb.t_bond_ann_info where create_time >= ‘2018-03-09 14:00:00‘;

3.Select a.* from
dmdb.t_bond_ann_info a
where a.id not in (
select ann_id from  t_bond_ann_att_info
  where last_update_time 
 
>= ‘2018-03-09 14:00:00‘   
)
and  a.create_time >= ‘2018-03-09 14:00:00‘;

4.Select distinct a.ann_id from 
dmdb.t_bond_ann_att_info a
where a.ann_id not in (
select id from  t_bond_ann_info
  where create_time >= ‘2018-03-09 11:10:00‘   
)
and last_update_time >= ‘2018-03-09 11:10:00‘;

5.select  * from t_bond_ann_att_info where ann_id in
 
 (‘13441‘,‘13442‘)

6.delete from t_bond_ann_att_info where ann_id in (‘13441‘,‘13442‘)

7.Select * from dmdb.t_bond_ann_info 
order by  create_time DESC
limit 800

8.select * from dmdb.t_bond_ann_att_info where ann_id=15068
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1、查找表中多余的重復記錄，重復記錄是根據單個字段（peopleId）來判斷

select 
 
* from people
where peopleId in (select  peopleId  from  people  group  by  peopleId  having  count(peopleId) > 1)

 例二：

 select * from testtable
 where numeber in (select number from people group by number having count(number) > 1 )

 可以查出testtable表中number相同的記錄

2、刪除表中多余的重復記錄，重復記錄是根據單個字段（peopleId）來判斷，只留有rowid最小的記錄
delete from people 
where peopleId  in (select  peopleId  from people  group  by  peopleId   having  count(peopleId) > 1)
and rowid not in (select min(rowid) from  people  group by peopleId  having count(peopleId )>1)

3、查找表中多余的重復記錄（多個字段） 
select * fromvitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq  having count(*) > 1)

4、刪除表中多余的重復記錄（多個字段），只留有rowid最小的記錄
delete fromvitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查找表中多余的重復記錄（多個字段），不包含rowid最小的記錄
select * fromvitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

(二)
比方說在A表中存在一個字段“name”，而且不同記錄之間的“name”值有可能會相同，
現在就是需要查詢出在該表中的各記錄之間，“name”值存在重復的項；
Select Name,Count(*) From A Group By Name Having Count(*) > 1

如果還查性別也相同大則如下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

方法二
有兩個意義上的重復記錄，一是完全重復的記錄，也即所有字段均重復的記錄，二是部分關鍵字段重復的記錄，
比如Name字段重復，而其他字段不一定重復或都重復可以忽略。
1、對於第一種重復，比較容易解決，使用
select distinct * from tableName
就可以得到無重復記錄的結果集。

如果該表需要刪除重復的記錄（重復記錄保留1條），可以按以下方法刪除
select distinct * into #Tmp fromtableName
drop tabletableName
select * into tableName from#Tmp
drop table #Tmp

發生這種重復的原因是表設計不周產生的，增加唯一索引列即可解決。

2、這類重復問題通常要求保留重復記錄中的第一條記錄，操作方法如下

假設有重復的字段為Name,Address，要求得到這兩個字段唯一的結果集
select identity(int,1,1) as autoID, * into #Tmp fromtableName

select min(autoID) as autoID into #Tmp2 from #Tmp group byName,autoID

select * from #Tmp where autoID in(select autoID from #tmp2)

最後一個select即得到了Name，Address不重復的結果集（但多了一個autoID字段，實際寫時可以寫在select子句中省去此列）

(四)
查詢重復
select * from tablename where id in(
select id fromtablename 
group by id 
 having count(id) > 1 
)

SQL重復記錄查詢