題目鏈接：

http://acm.hdu.edu.cn/showproblem.php?pid=2191

題目大意：
中文題

思路：

裸的多重背包

 1 #include<iostream>
 2 #include<cstring>
 3 #include<cstdio>
 4 using namespace std;
 5 const int INF = 0x3f3f3f3f;
 6 const int maxn = 200 + 10;
 7 int T, n, m, cases;
 8 int cost[maxn], weight[maxn], amount[maxn], dp[maxn];
 
 9 void zeroone(int cost, int weight)
10 {
11     for(int i = n; i >= cost; i--)
12         dp[i] = max(dp[i], dp[i - cost] + weight);
13 }
14 void complete(int cost, int weight)
15 {
16     for(int i = cost; i <= n; i++)
17         dp[i] = max(dp[i], dp[i - cost] + weight);
18 }
19 void solve(int
 
 cost, int weight, int amount)
20 {
21     if(cost * amount >= n)
22         complete(cost, weight);
23     else
24     {
25         int k = 1;//二進制優化
26         while(k <= amount)
27         {
28             zeroone(k * cost, k * weight);
29             amount -= k;
30             k *= 2;
31         }
 
32         zeroone(amount * cost, amount * weight);
33     }
34 }
35 int main()
36 {
37     cin >> T;
38     while(T--)
39     {
40         cin >> n >> m;
41         memset(dp, 0, sizeof(dp));
42         for(int i = 0; i < m; i++)
43             cin >> cost[i] >> weight[i] >> amount[i];
44         for(int i = 0; i < m; i++)
45             solve(cost[i], weight[i], amount[i]);
46         cout<<dp[n]<<endl;
47     }
48     return 0;
49 }

hdu-2191 悼念512汶川大地震遇難同胞——珍惜現在，感恩生活---多重背包