[LeetCode] Swim in Rising Water 在上升的水中遊泳
阿新 • • 發佈:2018-05-10
uri depth rain location dir least lse tput wim . You can swim infinite distance in zero time. Of course, you must stay within the boundaries of the grid during your swim.
On an N x N grid
, each square grid[i][j]
represents the elevation at that point (i,j)
.
Now rain starts to fall. At time t
, the depth of the water everywhere is t
. You can swim from a square to another 4-directionally adjacent square if and only if the elevation of both squares individually are at most t
You start at the top left square (0, 0)
. What is the least time until you can reach the bottom right square (N-1, N-1)
?
Example 1:
Input: [[0,2],[1,3]] Output: 3 Explanation: At time0
, you are in grid location(0, 0)
. You cannot go anywhere else because 4-directionally adjacent neighbors have a higher elevation than t = 0. You cannot reach point(1, 1)
until time3
. When the depth of water is3
, we can swim anywhere inside the grid.
Example 2:
Input: [[0,1,2,3,4],[24,23,22,21,5],[12,13,14,15,16],[11,17,18,19,20],[10,9,8,7,6]] Output: 16 Explanation: 0 1 2 3 4 24 23 22 21 5 12 13 14 15 16 11 17 18 19 20 10 9 8 7 6 The final route is marked in bold. We need to wait until time 16 so that (0, 0) and (4, 4) are connected.
Note:
2 <= N <= 50
.- grid[i][j] is a permutation of [0, ..., N*N - 1].
s
[LeetCode] Swim in Rising Water 在上升的水中遊泳