1. /*將int轉為低字節在前，高字節在後的byte數組
2. b[0] = 11111111(0xff) & 01100001
3. b[1] = 11111111(0xff) & (n >> 8)00000000
4. b[2] = 11111111(0xff) & (n >> 8)00000000
5. b[3] = 11111111(0xff) & (n >> 8)00000000
6. */
7. public byte[] IntToByteArray(int n) {
8. byte[] b = new byte[4];
9. b[0] = (byte) (n & 0xff);
10. b[1] = (byte) (n >> 8 & 0xff);
11. b[2] = (byte) (n >> 16 & 0xff);
12. b[3] = (byte) (n >> 24 & 0xff);
13. return b;
14. }
15. //將低字節在前轉為int，高字節在後的byte數組(與IntToByteArray1想對應)
16. public int ByteArrayToInt(byte[] bArr) {
17. if(bArr.length!=4){
18. return -1;
19. }
20. return (int) ((((bArr[3] & 0xff) << 24)
21. | ((bArr[2] & 0xff) << 16)
22. | ((bArr[1] & 0xff) << 8)
23. | ((bArr[0] & 0xff) << 0)));
24. }
26. 
    
    1. public static byte[] double2Bytes(double d) {
    2. long value = Double.doubleToRawLongBits(d);
    3. byte[] byteRet = new byte[8];
    4. for (int i = 0; i < 8; i++) {
    5. byteRet[i] = (byte) ((value >> 8 * i) & 0xff);
    6. }
    7. return byteRet;
    8. }
       
       1. public static double bytes2Double(byte[] arr) {
       2. long value = 0;
       3. for (int i = 0; i < 8; i++) {
       4. value |= ((long) (arr[i] & 0xff)) << (8 * i);
       5. }
       6. return Double.longBitsToDouble(value);
       7. }

byteArray轉換為double,int