JAVA多線程筆試題
阿新 • • 發佈:2018-08-22
技術 答案 args disable this arraylist null mit tex 一、題目內容
二、我的答案
利用了線程池、考慮了超時處理、不知道這樣寫是否還有其他問題,或者更好更優的解決方案?
import java.util.;
import java.util.concurrent.;public class Main {
public static void main(String[] args) { List<String> allPaymentList=Arrays.asList("余額","紅包","余額寶","銀行卡"); long start=System.nanoTime(); List<String> list=filterDisablePayment(allPaymentList); double seconds=(System.nanoTime()-start)/1000000000.0; System.out.println("總共耗時:"+seconds+"s"); for(String paymentType:list){ System.out.println(paymentType); } } public static List<String> filterDisablePayment(List<String> allPaymentList){ List<String> results=new ArrayList<>(); ExecutorService executorService= Executors.newFixedThreadPool(allPaymentList.size()); List<Future<String>> futures=new ArrayList<>(); for(String paymentType:allPaymentList) { futures.add(executorService.submit(new PaymentMethodCallable(paymentType))); } executorService.shutdown(); for(Future<String> future:futures){ try { //超時處理機制 String result= future.get(4,TimeUnit.SECONDS); if(result!=null){ results.add(result); } } catch (Exception e) { e.printStackTrace(); } } return results; } public static Boolean PaymentIsEnabled(String paymentType) { try { //模擬遠程服務調用所用時間 Thread.sleep(3000); Random random=new Random(); boolean result=random.nextBoolean(); System.out.println("獲取到結果:"+paymentType+":"+result); return result; } catch (Exception e) { e.printStackTrace(); } return false; } static class PaymentMethodCallable implements Callable<String> { private String paymentType; public String getPaymentType() { return paymentType; } public void setPaymentType(String paymentType) { this.paymentType = paymentType; } public PaymentMethodCallable(String paymentType) { this.paymentType = paymentType; } @Override public String call() { if(PaymentIsEnabled(paymentType)) return paymentType; return null; } }
}
JAVA多線程筆試題