python實現單單鏈表
阿新 • • 發佈:2018-09-29
war 是否 utf append emp auth 添加 pychar sea
# -*- coding: utf-8 -*- # @Time : 2018/9/28 22:09 # @Author : cxa # @File : node.py # @Software: PyCharm # 單向列表 # 數據元素區,下一個結點的鏈接區 # 尾節點指向的結點為空。 """ 表元素域 下一結點鏈接域 """ class Node: # 結點類 def __init__(self, elem): self.elem = elem self.next = None class SingLinkList(object): # 鏈表類 def __init__(self, node=None): self.__head = node def is_empty(self): """列表是否為空""" return self.__head == None def length(self): """結點的數目,到尾節點截止。需要一個遊標、來記錄當前的位置""" cur = self.__head """count記錄數量,如果空鏈表也可以正確處理""" count = 0 """開始遊標移動""" while cur: count += 1 cur = cur.next return count def travel(self): """遍歷列表""" cur = self.__head while cur: print("當前的結點", cur.elem, end=‘‘) cur = cur.next def add(self, item): """從頭部添加,頭插法""" node = Node(item) node.next = self.__head self.__head = node def append(self, item): """從尾部添加,尾插法""" node = Node(item) if self.is_empty(): self.__head = node else: cur = self.__head while cur.next: cur = cur.next cur.next = node def insert(self, pos, item): node = Node(item) ‘‘‘ 從指定位置添加 :param pos: 從0開始 :param item: :return: ‘‘‘ if pos <= 0: self.add(item) elif pos > self.length(item) - 1: self.append(item) else: pre = self.__head # pre指前一個對象 count = 0 while count < pos - 1: count += 1 pre = pre.next # pre指向poss-1 node.next = pre.next pre.next = node def remove(self, item): """刪除結點""" # pre.next=pre.next.next cur = self.__head pre = None while cur: if cur.elem == item: # 判斷此節點是否是頭節點 # 頭節點 if cur == self.__head: self.__head = cur.next else: pre.next = cur.next break else: pre = cur cur = cur.next def search(self, item): """查找結點是否存在""" cur = self.__head while cur: if cur.elem == item: return True else: cur = cur.next return False if __name__ == ‘__main__‘: # 測試下正確性 ll = SingLinkList() print(ll.is_empty()) print(ll.length()) ll.append(1) print(ll.is_empty()) print(ll.length()) ll.append(2) ll.append(3) ll.add(8) ll.append(4) ll.travel()
python實現單單鏈表