[LeetCode] 905. Sort Array By Parity(C++)
阿新 • • 發佈:2018-11-03
Given an array A
of non-negative integers, return an array consisting of all the even elements of A
, followed by all the odd elements of A
.
You may return any answer array that satisfies this condition.
Example 1:
Input: [3,1,2,4] Output: [2,4,3,1] The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.
Note:
1 <= A.length <= 5000
0 <= A[i] <= 500
class Solution { public: vector<int> sortArrayByParity(vector<int>& A) { int l = 0, r = A.size() - 1; while (l < r) { while (A[l] % 2 == 0) l++; while (A[r] % 2 == 1) r--; if (l < r) swap(A[l++], A[r--]); } return A; } void swap(int& left, int& right) { int temp = left; left = right; right = temp; } };