iOS資料庫操作
iOS的資料庫是sqlite3,是模糊型別的資料庫，但是仍然不能隨便定義資料型別
* 使用時首先匯入資料庫包，然後宣告資料庫變數：sqlite3 *db;
* 開啟資料庫：
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *documents = [paths objectAtIndex:0];
NSString *database_path = [documents stringByAppendingPathComponent:dbName];
if (sqlite3_open([database_path UTF8String], &db) != SQLITE_OK) {
sqlite3_close(db);
NSLog(@"資料庫開啟失敗");
}
* 建表並插入資料：
NSString *sqlCreateTable = @”CREATE TABLE IF NOT EXISTS USERS2 (ID INTEGER PRIMARY KEY AUTOINCREMENT, name TEXT, sex TEXT,password TEXT,phone TEXT, location TEXT)”;
[self execSql:sqlCreateTable];
char *update = “INSERT OR REPLACE INTO USERS2(name,sex,password,phone,location)”“VALUES(?,?,?,?,?);”;
char *errorMsg = NULL; sqlite3_stmt *stmt; if (sqlite3_prepare_v2(db, update, -1, &stmt, nil) == SQLITE_OK) { //【插入資料】在這裡我們使用繫結資料的方法，引數一：sqlite3_stmt，引數二：插入列號，引數三：插入的資料，引數四：資料長度（-1代表全部），引數五：是否需要回調 sqlite3_bind_text(stmt, 1, [userNameText.text UTF8String], -1, NULL); sqlite3_bind_text(stmt, 2, [xingBei UTF8String], -1, NULL); sqlite3_bind_text(stmt, 3, [passText.text UTF8String], -1, NULL); sqlite3_bind_text(stmt, 4, [phoneText.text UTF8String], -1, NULL); sqlite3_bind_text(stmt, 5, [diZhiText.text UTF8String], -1, NULL); } NSLog(@"yuyuyuyuyyyyyyyyyyyyyyyyyyyyyy"); if (sqlite3_step(stmt) != SQLITE_DONE) NSLog(@"資料更新失敗"); }
* 查詢內容：
NSString sqlQuery = @”SELECT FROM USERS2”;
sqlite3_stmt *statement;
if (sqlite3_prepare_v2(db, [sqlQuery UTF8String], -1, &statement, nil) == SQLITE_OK) {
while (sqlite3_step(statement) == SQLITE_ROW) {
char *name = (char*)sqlite3_column_text(statement, 1);
NSString *nsNameStr = [[NSString alloc]initWithUTF8String:name];
char *password=(char*)sqlite3_column_text(statement, 3);
NSString *nsPasswordStr=[[NSString alloc]initWithUTF8String:password];
NSLog(@"name:%@ password:%@ ",nsNameStr,nsPasswordStr);
}
}
* 刪除內容：
NSString *sqlQuery2 = @”DELETE FROM USERS2 WHERE name =’Wx’ “;
if (sqlite3_prepare_v2(db, [sqlQuery2 UTF8String], -1, &statement, nil) == SQLITE_OK) {
while (sqlite3_step(statement) == SQLITE_ROW) {
}
}