#Leetcode# 58. Length of Last Word
阿新 • • 發佈:2018-11-05
https://leetcode.com/problems/length-of-last-word/description/
Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example:
Input: "Hello World" Output: 5
程式碼:
class Solution { public: int lengthOfLastWord(string s) { int len = s.length(); int ans = 0; int temp = 0; for(int i = len - 1; i >= 0; i --) { if(s[i] != ' ') { temp = i; break; } } for(int i = temp; i >= 0; i --) { if(s[i] != ' ') ans ++; else break; } return ans; } };