leetcode - 500 - 鍵盤行
阿新 • • 發佈:2018-11-06
注意初始化
class Solution: def findWords(self, words): """ :type words: List[str] :rtype: List[str] """ L1 = ["q","w","e","r","t","y","u","i","o","p"] L2 = ["a","s","d","f","g","h","j","k","l"] L3 = ["z","x","c","v","b","n","m"] a=0 b=0 c=0 out = [] for word in words: wo = word.lower() for i in range(len(wo)): if wo[i] in L1: a+=1 continue elif wo[i] in L2: b+=1 continue else: c+=1 continue if a==len(wo) or b==len(wo) or c==len(wo): out.append(word) a,b,c = 0,0,0 # 注意初始化 else: a,b,c = 0,0,0 #### return out