JS 獲取鏈接中的參數
阿新 • • 發佈:2018-11-07
split turn 獲取 字串 pan != return oca quest
1、獲取鏈接全部參數,以對象的形式返回
//獲取url中參數 function GetRequest() { var url = location.search; //獲取url中"?"符後的字串 var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for (var i = 0; i < strs.length; i++) { theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]); } } }
2、根據參數名獲取鏈接中的參數值
function GetRequest2(key) { var url = location.search; var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for (vari = 0; i < strs.length; i++) { theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]); } } var value = theRequest[key]; return value; }
JS 獲取鏈接中的參數