Java 使用ZipOutputStream 進行打包操作
阿新 • • 發佈:2018-11-07
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打包單個檔案:
public static void main(String[] args) throws IOException{ File file = new File("d:" + File.separator + "aaa.java"); File zipFile = new File("d:" + File.separator + "hello.zip"); InputStream input = new FileInputStream(file); ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream( zipFile)); zipOut.putNextEntry(new ZipEntry(file.getName())); // 設定註釋 zipOut.setComment("hello" ); int temp = 0; while((temp = input.read()) != -1){ zipOut.write(temp); } input.close(); zipOut.close(); }
打包多個檔案:
public static void main(String[] args) throws IOException{ // 要被壓縮的資料夾 File file = new File("d:" + File.separator + "temp"); File zipFile = new File("d:" + File.separator + "zipFile.zip"); InputStream input = null; ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream( zipFile)); zipOut.setComment("hello"); if(file.isDirectory()){ File[] files = file.listFiles(); for(int i = 0; i < files.length; ++i){ input = new FileInputStream(files[i]); zipOut.putNextEntry(new ZipEntry(file.getName() + File.separator + files[i].getName())); int temp = 0; while((temp = input.read()) != -1){ zipOut.write(temp); } input.close(); } } zipOut.close(); }
大家自然想到,既然能壓縮,自然能解壓縮,在談解壓縮之前,我們會用到一個ZipFile類,先給一個這個例子吧。java中的每一個壓縮檔案都是可以使用ZipFile來進行表示的
import java.io.File;import java.io.IOException;import java.util.zip.ZipFile; /** * ZipFile演示 * */public class ZipFileDemo{ public static void main(String[] args) throws IOException{ File file = new File("d:" + File.separator + "hello.zip"); ZipFile zipFile = new ZipFile(file); System.out.println("壓縮檔案的名稱為:" + zipFile.getName()); }}
解壓單個檔案:
public static void main(String[] args) throws IOException{ File file = new File("d:" + File.separator + "hello.zip"); File outFile = new File("d:" + File.separator + "unZipFile.txt"); ZipFile zipFile = new ZipFile(file); ZipEntry entry = zipFile.getEntry("hello.txt");//hello.txt 為壓縮包中檔案的名稱 InputStream input = zipFile.getInputStream(entry); OutputStream output = new FileOutputStream(outFile); int temp = 0; while((temp = input.read()) != -1){ output.write(temp); } input.close(); output.close(); }
解壓多個檔案:
當我們需要解壓縮多個檔案的時候,ZipEntry就無法使用了,如果想操作更加複雜的壓縮檔案,我們就必須使用ZipInputStream類
public static void main(String[] args) throws IOException{ File file = new File("d:" + File.separator + "zipFile.zip"); File outFile = null; ZipFile zipFile = new ZipFile(file); ZipInputStream zipInput = new ZipInputStream(new FileInputStream(file)); ZipEntry entry = null; InputStream input = null; OutputStream output = null; while((entry = zipInput.getNextEntry()) != null){ System.out.println("解壓縮" + entry.getName() + "檔案");//entry.getName()獲得壓縮包內的檔案及檔案路徑(aaaa/bb.txt) outFile = new File("d:" + File.separator + entry.getName()); if(!outFile.getParentFile().exists()){ outFile.getParentFile().mkdir(); } if(!outFile.exists()){ outFile.createNewFile(); } input = zipFile.getInputStream(entry); output = new FileOutputStream(outFile); int temp = 0; while((temp = input.read()) != -1){ output.write(temp); } input.close(); output.close(); } }