25. 獲取員工其當前的薪水比其manager當前薪水還高的相關資訊
題目描述
獲取員工其當前的薪水比其manager當前薪水還高的相關資訊,當前表示to_date='9999-01-01',
結果第一列給出員工的emp_no,
第二列給出其manager的manager_no,
第三列給出該員工當前的薪水emp_salary,
第四列給該員工對應的manager當前的薪水manager_salary
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
輸入描述:
無
輸出描述:
emp_no |
manager_no |
emp_salary |
manager_salary |
---|---|---|---|
10001 |
10002 |
88958 |
72527 |
10009 |
10010 |
95409 |
94409 |
SELECT d1.emp_no AS emp_no, d2.emp_no AS manager_no, d1.salary AS emp_salary, d2.salary AS manager_salary FROM ( dept_emp d INNER JOIN salaries s ON d.emp_no = s.emp_no AND s.to_date = '9999-01-01' ) AS d1, ( dept_manager m INNER JOIN salaries s ON m.emp_no = s.emp_no AND s.to_date = '9999-01-01' ) AS d2 WHERE d1.salary > d2.salary AND d1.dept_no = d2.dept_no;