BigDecimal 的add方法,結果竟然沒變??
阿新 • • 發佈:2018-11-08
@Test
public void testBigDecimal(){
BigDecimal decimal1=new BigDecimal("0");
BigDecimal decimal2=new BigDecimal(2);
decimal1.add(decimal2);
System.out.println(decimal1.add(decimal1));
System.out.println(decimal1.add(decimal2));
}
結果輸出:
神不神奇,意不意外,a.add(b) ,a的值沒變
而是a.add 方法返回 a+b的值
具體看原始碼:
/** * Returns a {@code BigDecimal} whose value is {@code (this + * augend)}, and whose scale is {@code max(this.scale(), * augend.scale())}. * * @param augend value to be added to this {@code BigDecimal}. * @return {@code this + augend} (返回和) */ public BigDecimal add(BigDecimal augend) { if (this.intCompact != INFLATED) { if ((augend.intCompact != INFLATED)) { return add(this.intCompact, this.scale, augend.intCompact, augend.scale); } else { return add(this.intCompact, this.scale, augend.intVal, augend.scale); } } else { if ((augend.intCompact != INFLATED)) { return add(augend.intCompact, augend.scale, this.intVal, this.scale); } else { return add(this.intVal, this.scale, augend.intVal, augend.scale); } } }
可以看到是return 一個值