Java判斷一個時間是否在時間區間內
阿新 • • 發佈:2018-11-09
package com.liying.tiger.test;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
public class Test {
public static void main(String[] args) throws ParseException {
String format = “HH:mm:ss”;
Date nowTime = new SimpleDateFormat(format).parse(“09:27:00”);
Date startTime = new SimpleDateFormat(format).parse(“09:27:00”);
Date endTime = new SimpleDateFormat(format).parse(“09:27:59”);
System.out.println(isEffectiveDate(nowTime, startTime, endTime));
}
/** * 判斷當前時間是否在[startTime, endTime]區間,注意時間格式要一致 * * @param nowTime 當前時間 * @param startTime 開始時間 * @param endTime 結束時間 * @return * @author jqlin */ public static boolean isEffectiveDate(Date nowTime, Date startTime, Date endTime) { if (nowTime.getTime() == startTime.getTime() || nowTime.getTime() == endTime.getTime()) { return true; } Calendar date = Calendar.getInstance(); date.setTime(nowTime); Calendar begin = Calendar.getInstance(); begin.setTime(startTime); Calendar end = Calendar.getInstance(); end.setTime(endTime); if (date.after(begin) && date.before(end)) { return true; } else { return false; } }
}