使用jdk的jws實現 開發web services
首先web.xml 必須要有對org.springframework.web.context.ContextLoaderListener支援
<listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
java 檔案：
import javax.jws.soap.SOAPBinding.Style;
@Service("soapService")
@WebService(serviceName = "soap")
@SOAPBinding(style=Style.RPC)
public class SOAPImpl {
@Autowired
private DictionaryManager dictManger;
@WebMethod
public String datacatalog(String datacatalogcode) {
List<FDatacatalog> datalog = dictManger.getUserCdctgs();
return datalog.get(0).getCatalogname();
}
}
beans.xml(spring配置檔案)
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context
xmlns:jee="http://www.springframework.org/schema/jee" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:task="http://www.springframework.org/schema/task"
xsi:schemaLocation="
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/task http://www.springframework.org/schema/task/spring-task-3.0.xsd">
<context:component-scan base-package="com.centit.dde.cxf" />
<bean class="org.springframework.remoting.jaxws.SimpleJaxWsServiceExporter">
<property name="baseAddress" value="http://localhost:8081/" />
</bean>
</beans>