leetcode【537】Complex Number Multiplication(複數相乘)
阿新 • • 發佈:2018-11-13
寫在最前面:一道很常規的字串分割的題
leetcode【537】Complex Number Multiplication
Given two strings representing two complex numbers.
You need to return a string representing their multiplication. Note i2 = -1 according to the definition.
Example 1:
Input: "1+1i", "1+1i" Output: "0+2i" Explanation:(1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i, and you need convert it to the form of 0+2i.
Example 2:
Input: "1+-1i", "1+-1i" Output: "0+-2i" Explanation: (1 - i) * (1 - i) = 1 + i2 - 2 * i = -2i, and you need convert it to the form of 0+-2i.
Note:
- The input strings will not have extra blank.
- The input strings will be given in the form of a+bi, where the integer a and b will both belong to the range of [-100, 100]. And the output should be also in this form.
class Solution(object): def complexNumberMultiply(self, a, b): """ :type a: str :type b: str :rtype: str """ sub1 = int(a.split('+')[0]) *int( b.split('+')[0]) sub2 = int(a.split('+')[0]) * int(b.split('+')[1][:-1]) sub3 = int(a.split('+')[1][:-1]) * int(b.split('+')[0]) sub4 = int(a.split('+')[1][:-1]) * int(b.split('+')[1][:-1]) sum = sub1 + sub4*-1 return str(sum) + '+'+str(sub2+sub3)+'i'