Oracle row_number dense_rank rank() 用法
阿新 • • 發佈:2018-11-22
Oracle row_number
dense_rank
rank
看結果集的倒數 2 3 行資料就明白了.
[email protected]>select * from emp;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- --------- ---------- ---------- ----------
7369 SMITH CLERK 7902 17-DEC-80 800 20
7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30
7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30
7566 JONES MANAGER 7839 02-APR-81 2975 20
7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30
7698 BLAKE MANAGER 7839 01-MAY-81 2850 30
7782 CLARK MANAGER 7839 09-JUN-81 2450 10
7839 KING PRESIDENT 17-NOV-81 5000 10
7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30
7876 ADAMS CLERK 7788 23-MAY-87 1100 20
7900 JAMES CLERK 7698 03-DEC-81 950 30
7902 FORD ANALYST 7566 03-DEC-81 3000 20
7934 MILLER CLERK 7782 23-JAN-82 1300 10
[email protected]>select ename,deptno,sal,row_number() over(partition by deptno order by sal desc) rn from emp;
ENAME DEPTNO SAL RN
---------- ---------- ---------- ----------
KING 10 5000 1
CLARK 10 2450 2
MILLER 10 1300 3
FORD 20 3000 1
JONES 20 2975 2
ADAMS 20 1100 3
SMITH 20 800 4
BLAKE 30 2850 1
ALLEN 30 1600 2
TURNER 30 1500 3
MARTIN 30 1250 4
WARD 30 1250 5
JAMES 30 950 6
[email protected]>select ename,deptno,sal,dense_rank() over(partition by deptno order by sal desc) rn from emp;
ENAME DEPTNO SAL RN
---------- ---------- ---------- ----------
KING 10 5000 1
CLARK 10 2450 2
MILLER 10 1300 3
FORD 20 3000 1
JONES 20 2975 2
ADAMS 20 1100 3
SMITH 20 800 4
BLAKE 30 2850 1
ALLEN 30 1600 2
TURNER 30 1500 3
MARTIN 30 1250 4
WARD 30 1250 4
JAMES 30 950 5
[email protected]>select ename,deptno,sal,rank() over(partition by deptno order by sal desc) rn from emp;
ENAME DEPTNO SAL RN
---------- ---------- ---------- ----------
KING 10 5000 1
CLARK 10 2450 2
MILLER 10 1300 3
FORD 20 3000 1
JONES 20 2975 2
ADAMS 20 1100 3
SMITH 20 800 4
BLAKE 30 2850 1
ALLEN 30 1600 2
TURNER 30 1500 3
MARTIN 30 1250 4
WARD 30 1250 4
JAMES 30 950 6