1. 程式人生 > >4 重建二叉樹

4 重建二叉樹

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* reConstructBinaryTree(vector<int> pre,vector<int> vin) {
        int
len = pre.size(); if(len == 0) return NULL; int idx; for(int i = 0; i < len; ++i){ if(vin[i] == pre[0]){ idx = i; break; } } vector<int> pre_left, pre_right, vin_left, vin_right; for(int i = 0
; i< idx; ++i){ pre_left.push_back(pre[i+1]); vin_left.push_back(vin[i]); } for(int i = idx + 1; i < len; ++i){ pre_right.push_back(pre[i]); vin_right.push_back(vin[i]); } TreeNode* head = new TreeNode(pre[0]); head->left = reConstructBinaryTree(pre_left, vin_left); head->right = reConstructBinaryTree(pre_right, vin_right); return
head; } };