Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

Output

One integer per line representing the maximum of the total value (this number will be less than 231).

Sample Input

1
5 10
1 2 3 4 5
5 4 3 2 1

Sample Output

14

Author

Teddy

Source

HDU 1st “Vegetable-Birds Cup” Programming Open Contest

思路

簡單的01揹包問題。

因為不用恰好裝滿，所以初始化的時候\(f[i]\)全都初始化為0

程式碼

#include<bits/stdc++.h>
using namespace std;
int value[1001];
int cost[1001];
int f[1001];
int main()
{
    int T;
    cin >> T;
    while(T--)
    {
        int n,v;
        cin >> n >> v;
        memset(f,0,sizeof(f));
        for(int i=1;i<=n;i++)   cin >> value[i];//價值
        for(int i=1;i<=n;i++)   cin >> cost[i];//花費
        for(int i=1;i<=n;i++)
            for(int j=v;j>=cost[i];j--)
                f[j] = max(f[j], f[j-cost[i]]+value[i]);
        cout << f[v] << endl;
    }
    return 0;
}