Q1:20120007,
SELECT
stu_name,stu_gender,stu_birthday
FROM
t_student
WHERE
stu_id = 20127007

Q2:會計1201,find student"s id & name
SELECT
a.stu_id,a.stu_name
FROM
t_student as a
INNER JOIN t_class b ON b.cls_id = a.cls_id
WHERE b.cls_name = '會計1201'

Q3：會計，2012，find classes with students' couunt
SELECT
count(b.stu_id)
FROM
t_class a
inner join t_student b ON b.cls_id = a.cls_id
WHERE
a.grade = 2012
AND
    a.subject= '會計'
第二種

SELECT
a.cls_name,
count(*)
FROM t_class a
INNER JOIN t_student b ON a.cls_id = b.cls_id
WHERE
a.subject = '會計'
AND
a.grade = 2012
GROUP BY
    a.cls_name

Q4：20127007 find all failured course

SELECT
c.course_name
FROM t_mark a
INNER JOIN t_course c ON c.course_id = a.course_id

WHERE
a.stu_id = 20127001
AND
     a.scroll < 60


Q5:Add a new course,17317,'Course Foundation',3.5
INSERT INTO t_course (
course_id,course_name,course_credit)
VALUES
    (17317,'DB Foundation',3.5)

Q6:會計，2012，英語[1]，FIND avg
SELECT DISTINCT
avg(c.scoll)
FROM
t_class a
inner join t_student b ON b.cls_id = a.cls_id
inner join t_mark c ON b.stu_id = c.stu_id
inner join t_course d ON d.course_id = c.course_id
WHERE
a.grade = 2012
AND
a.subject = '會計'
AND
     d.course_name = '英語[1]'

Q7：會計，2012，英語[1]，failure students
SELECT DISTINCT
b.*
FROM
t_class a
inner join t_student b ON b.cls_id = a.cls_id
inner join t_mark c ON b.stu_id = c.stu_id
inner join t_course d ON d.course_id = c.course_id
WHERE
c.scroll < 60
AND
a.subject = '會計'
AND
     d.course_name = '英語[1]'
、方法2
SELECT
a.stu_id,a.stu_name
FROM t_student a
INNER JOIN t_class b ON a.cls_id = b.cls_id
WHERE
b.subject = '會計' AND b.grade = 2012
EXISTS(
SELECT 1 FROM t_mark c
INNER JOIN t_course d ON d.course_id = c.course_id]
WHERE
c.stu_id = a.stu_id
AND
c.scroll < 60
AND
d.course_name = '英語[1]'
    )


Q8：會計，2012，5-course-failure
SELECT DISTINCT
b.stu_name/*按分組的列顯示*/
FROM
t_class a
inner join t_student b ON b.cls_id = a.cls_id
inner join t_mark c ON b.stu_id = c.stu_id
inner join t_course d ON d.course_id = c.course_id
WHERE
c.scroll < 60
AND
a.subject = '會計'
AND
a.grade =2012
GROUP BY b.stu_name
HAVING count(distinct c.course_id) >=5


方法2
SELECT DISTINCT
b.stu_name,count(*),count(c.course_id)/*按分組的列顯示*/
FROM
t_class a
inner join t_student b ON b.cls_id = a.cls_id
inner join t_mark c ON b.stu_id = c.stu_id
inner join t_course d ON d.course_id = c.course_id
WHERE
c.scroll < 60
AND
a.subject = '會計'
AND
a.grade =2012
GROUP BY b.stu_name
HAVING count(distinct c.course_id) >=5