Conclusion of the first exam
1.假設在n進位制下,下面的等式成立,567*456=150216,n的值是多少()
A.9
B.10
C.12
D.18
解析:
第1步,由題可知:(5*n^2+6*n+7)*(4*n^2+5*n+6)==n^5+5*n^4+2*n^2+n+6,整理得:
20*n^4+49*n^3+88*n^2+71*n+42=n^5+5*n^4+2*n^2+n+6 (1)
第2步,對方程(1)兩邊同時對n取餘,得:42%n==6 (2)
由於此時只能排除B,故還得繼續尋找一個方程;
第3步,然後先對方程(1)除以n,再對n取餘,得:(71+42/n)%n==(1+6/n)%n (2)
此時再代入得:D滿足。
11.24修改
巨集的定義,使用時直接帶進去,譬如定義函式F=x*y+z
現在x=a+b,y=b+c,z=c+a,所以函式值就為F=a+b*b+c+c+a。
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