題目連結：https://pan.baidu.com/s/1ihUShawo9-21IwSYhq7NiA  　　密碼：jrou

題目邏輯很簡單，將輸入在函式sub_4005B6()進行處理，然後和dword_601060陣列中的資料比較。

看一下，sub_4005B6函式，邏輯也很簡單。

我們把byte_6010C0處存放的15000個數據dump下來，然後寫指令碼即可得到flag。

arr = open("E://data","rb").read()
flag = [0xc4,0x34,0x22,0xb1,0xd3,0x11,
        0x97,0x07,0xdb,0x37,0xc4,0x06,
        
 
0x1d,0xfc,0x5b,0xed,0x98,0xdf,
        0x94,0xd8,0xb3,0x84,0xcc,0x08]
for i in range(14997,-1,-3):
    a = arr[i]
    b = arr[i+1]
    c = arr[i+2]
    if(a == 1):
        flag[b] -= c
        flag[b] = flag[b]&0xff
    if(a == 2):
        flag[b] += c
        flag[b] = flag[b] & 0xff
    if(a == 3):
        flag[b] 
 
^= c
        flag[b] = flag[b] & 0xff
    if(a == 4):
        flag[b] /= c
        flag[b] = flag[b] & 0xff
    if(a == 5):
        flag[b] ^= flag[c]
        flag[b] = flag[b] & 0xff
print(''.join(map(chr,flag)))