自定義 lsn 命令, 列印第 n 個檔案的內容
阿新 • • 發佈:2018-12-04
lsn:
# add by cw # aim: print nth file contents if [ $# -eq 1 ]; then xnd=`echo $1'p'` nfilename=`ls | sed -n $xnd` echo 'filename:'\<$nfilename\> if [ -d "$nfilename" ]; then echo "is a directory!" exit fi echo '------------- contents: --------------' ls | sed -n $xnd | xargs cat elif [ $# -eq 2 ]; then xnd=`echo $2'p'` nfilename=`ls $1 | sed -n $xnd` echo 'filename:'\<$nfilename\> echo '------------- contents: --------------' file2=`ls $1 | sed -n $xnd` abs_path=`echo $1\/$file2` if [ -d "$abs_path" ]; then echo "is a directory!" exit fi cat $abs_path echo '' else echo "lsn parameter error" fi