轉載: http://blog.51cto.com/lizhenliang/1875330

程式碼

#!/usr/bin/python
# -*- coding: utf-8 -*-
import smtplib

def sendMail(body):
    smtp_server = 'smtp.163.com'
    from_mail = '[email protected]'
    mail_pass = 'your_email_password'
    to_mail = ['[email protected]', '[email protected]
 
']
    cc_mail = ['[email protected]']
    from_name = 'monitor' 
    subject = u'[重要通知][CW] xxx 程式已執行到預定位置, 請及時處理!'.encode('gbk')   # 以gbk編碼傳送，一般郵件客戶端都能識別
#     msg = '''\
# From: %s <%s>
# To: %s
# Subject: %s
# %s''' %(from_name, from_mail, to_mail_str, subject, body)  # 這種方式必須將郵件頭資訊靠左，也就是每行開頭不能用空格，否則報SMTP 554
    mail = [
        "From: %s <%s>" % (from_name, from_mail),
        "To: %s" % ','.join(to_mail),   # 轉成字串，以逗號分隔元素
        "Subject: %s" % subject,
        "Cc: %s" % ','.join(cc_mail),
        "",
        body
        ]
    msg = '\n'.join(mail)  # 這種方式先將頭資訊放到列表中，然後用join拼接，並以換行符分隔元素，結果就是和上面註釋一樣了
    try:
        s = smtplib.SMTP()
        s.connect(smtp_server, '25')
        s.login(from_mail, mail_pass)
        s.sendmail(from_mail, to_mail+cc_mail, msg)   
        s.quit()
    except smtplib.SMTPException as e:
        print "Error: %s" %e

if __name__ == "__main__":
    sendMail("[Sending Reason] Aliyun had a list overflow event, please deal with it in time! \n\nMore Details: ......")