別人很好的解題思路

https://www.nowcoder.com/questionTerminal/5f3b7bf611764c8ba7868f3ed40d6b2c

我的思路

package design;

import java.util.HashSet;
import java.util.Set;

public class Solution {
    int len=999;
    int can[][] = new int[len+1][len+1];
    int visit[][] = new int[len+1][len+1];

    int Can(String s, Set<String> dict, int
 
 start, int endd) {
        System.out.println(s.substring(start, endd));
        if (dict.contains(s.substring(start, endd)))    
            return 1;
        return 0;

    }

    int ok(String s, Set<String> dict, int start, int endd) {
        
        if (visit[start][endd] == 0) {
            visit[start][endd] 
 
= 1;
            if (Can(s, dict, start, endd) == 1) {
                can[start][endd] = 1;
            } else {
                for (int i = start + 1; i < endd; i++) {
                    
                    can[start][i] = ok(s, dict, start, i);
                    can[i][endd] = ok(s, dict, i , endd);
                    
 
if (can[start][i] == 1 && can[i][endd] == 1) {
                        can[start][endd] = 1;
                        break;
                    }
                }
            }

        }
        System.out.println(start+" "+endd+" "+can[start][endd]);
        return can[start][endd];

    }

    public boolean wordBreak(String s, Set<String> dict) {
        len = s.length();
         if(ok(s,dict,0,len)==1) return true;
         return false;
 
    }
    public static void main(String args[]) {
        Set<String> a=new HashSet<String>();
        String s="sad";
        
        a.add("sa");
        a.add("d");
        Solution ss=new Solution();
        //System.out.println(s.substring(0, 2));
        System.out.println(ss.wordBreak(s,a));
        
    }
}