LeetCode-Easy刷題(33) Min Stack
阿新 • • 發佈:2018-12-04
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- getMin() -- Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.getMin(); --> Returns -3. minStack.pop(); minStack.top(); --> Returns 0. minStack.getMin(); --> Returns -2.
建立一個棧物件,實現相應的方法.
public class MinStack { private int top = 0; private int[] stack; private int[] minStack; private int minTop=-1; /** initialize your data structure here. */ public MinStack() { stack = new int[8]; minStack = new int[8]; } public void push(int x) { stack[top] = x; if(minTop <0 ||minStack[minTop] >=x){ minTop++; minStack[minTop] = x; } if(minTop>=minStack.length-1){ int[] newStack = new int[top*2]; for (int i = 0; i < minStack.length; i++) { newStack[i] = minStack[i]; } minStack = newStack; } top++; if(top >=stack.length){ int[] newStack = new int[top*2]; for (int i = 0; i < stack.length; i++) { newStack[i] = stack[i]; } stack = newStack; } } public void pop() { int remove = stack[top-1]; stack[top-1]=0; top--; if(remove ==minStack[minTop]){ minStack[minTop] = 0; minTop--; } } public int top() { return stack[top-1]; } public int getMin() { return minStack[minTop]; } }