1. 程式人生 > >SqlServer如何判斷欄位中是否含有漢字?

SqlServer如何判斷欄位中是否含有漢字?

--/* 
--unicode編碼範圍: 
--漢字:[0x4e00,0x9fa5](或十進位制[19968,40869]) 
--數字:[0x30,0x39](或十進位制[48, 57]) 
--小寫字母:[0x61,0x7a](或十進位制[97, 122]) 
--大寫字母:[0x41,0x5a](或十進位制[65, 90]) 
--根據編碼範圍來判斷 
--*/
--建立
 
create proc p_A_VIC 
as 
declare @count int 
declare @i int 
declare @text nvarchar(50) 
set @i = 0
set @count = (select COUNT
(*) from table ) while(@i < @count ) begin set @i +=1 --sid代表有一定迴圈規律的,若是無序的可以新增一個序列(Row_Number() OVER ---)。 --select * from (SELECT *, Row_Number() OVER ( ORDER BY [sid] ) num FROM s--table ) as s where num = 3 set @text = (select a from table where [sid] = @i) if unicode(@text
) between 19968 And 40869 or unicode(@text) between 97 And 122 or unicode('a') between 65 And 90 begin print 0 end else print @text end --執行 exec p_A_VIC

例項1:

---由於某些原因HouseName 欄位存入了GUID,為了區分
SELECT HouseName FROM ZSGYTD_HouseInfo 
SELECT HouseName FROM ZSGYTD_HouseInfo WHERE
UNICODE(HouseName) BETWEEN 19968 AND 40869

執行結果:

 

例項2:

----將上述存入ZSGYTD_Estate 表ID的houseName進行左連線,獲取到對應的Name
SELECT h.HouseName,
CASE WHEN UNICODE(h.HouseName) BETWEEN 19968 AND 40869 then h.HouseName 
     ELSE e.Name
     END housename2    
FROM ZSGYTD_HouseInfo  h
LEFT JOIN ZSGYTD_Estate e ON CONVERT(varchar(50),e.ID)=h.HouseName and e.IsDeleted=0 


select*from ZSGYTD_Estate

執行結果: