集合排序(list)
1.Comparable自然規則排序
//在自定義類Student裡面實現Comparable介面,並重寫抽象方法compareTo(Student o);
//Collections.sort(集合);
public static void main(String[] args) {
List<Integer> nums = new ArrayList<Integer>();
nums.add(3);
nums.add(5);
nums.add(1);
nums.add(0);
System.out.println(nums);
Collections.sort(nums);
System.out.println(nums);
}
輸出結果:
[3, 5, 1, 0]
[0, 1, 3, 5]
稍微複雜的List裡面放一個複雜的物件
package core.java.collection.collections;
public class User implements Comparable<User>{
private int score;
private int age;
public User(int score, int age){
super();
this.score = score;
this.age = age;
}
public int getScore() {
return score;
}
public void setScore(int score) {
this.score = score;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
@Override
public int compareTo(User o) {
int i = this.getAge() - o.getAge();//先按照年齡排序
if(i == 0){
return this.score - o.getScore();//如果年齡相等了再用分數進行排序
}
return i;
}
}
public static void main(String[] args) {
List<User> users = new ArrayList<User>();
users.add(new User(78, 26));
users.add(new User(67, 23));
users.add(new User(34, 56));
users.add(new User(55, 23));
Collections.sort(users);
for(User user : users){
System.out.println(user.getScore() + "," + user.getAge());
}
}