PAT (Advanced Level) Practice 1106 Lowest Price in Supply Chain (25 分)
阿新 • • 發佈:2018-12-07
#include<cstdio>
#include<vector>
#include<cmath>
using namespace std;
const int N=1e5+5;
vector<int> G[N];
int num,n;
double mxx,p,r;
void dfs(int u,double sum)
{
int f=0;
for(int i=0;i<G[u].size();i++)
{
int v=G[u][i];
f=1;dfs(v,sum*(1+ 0.01*r));
}
if(!f)
{
if(sum-mxx<-1e-6) mxx=sum,num=1;
else if(fabs(sum-mxx)<1e-6) num++;
}
}
int main()
{
scanf("%d%lf%lf",&n,&p,&r);
for(int i=0;i<n;i++)
{
int x;scanf("%d",&x);
for(int j=0;j<x;j++)
{
int v;scanf("%d",&v);
G[i].push_back(v);
}
}
mxx=1e11;
dfs(0,p);
printf("%.4lf %d\n",mxx,num);
return 0;
}