python leetcode 49. Group Anagrams
阿新 • • 發佈:2018-12-08
對每個字串進行排序,那麼排序後Anagrams的字串是相同的
class Solution:
def groupAnagrams(self, strs):
"""
:type strs: List[str]
:rtype: List[List[str]]
"""
dict1={}
for i in range(len(strs)):
strsort = ''.join(sorted(strs[i]))
if not strsort in dict1:
dict1[strsort]=[i]
else:
dict1[strsort].append(i)
res=[]
for list1 in dict1.values():
temp=[]
for index in list1:
temp.append(strs[index])
res.append(temp)
return res