1124 Raffle for Weibo Followers(20 分)(cj)
1124 Raffle for Weibo Followers(20 分)
John got a full mark on PAT. He was so happy that he decided to hold a raffle(抽獎) for his followers on Weibo -- that is, he would select winners from every N followers who forwarded his post, and give away gifts. Now you are supposed to help him generate the list of winners.
Input Specification:
Each input file contains one test case. For each case, the first line gives three positive integers M (≤ 1000), N and S, being the total number of forwards, the skip number of winners, and the index of the first winner (the indices start from 1). Then M lines follow, each gives the nickname (a nonempty string of no more than 20 characters, with no white space or return) of a follower who has forwarded John's post.
Note: it is possible that someone would forward more than once, but no one can win more than once. Hence if the current candidate of a winner has won before, we must skip him/her and consider the next one.
Output Specification:
For each case, print the list of winners in the same order as in the input, each nickname occupies a line. If there is no winner yet, print Keep going...
Sample Input 1:
9 3 2
Imgonnawin!
PickMe
PickMeMeMeee
LookHere
Imgonnawin!
TryAgainAgain
TryAgainAgain
Imgonnawin!
TryAgainAgain
Sample Output 1:
PickMe
Imgonnawin!
TryAgainAgain
Sample Input 2:
2 3 5
Imgonnawin!
PickMe
Sample Output 2:
Keep going...
code
#pragma warning(disable:4996)
#include <iostream>
#include <algorithm>
#include <set>
#include <string>
#include <vector>
using namespace std;
int main() {
int m, n, s;
string str;
set<string> ss;
vector<string> vstr;
cin >> m >> n >> s;
for (int i = 0; i < m; ++i) {
cin >> str;
vstr.push_back(str);
}
int i = s-1;
bool f = 1;
while (i<m) {
if (ss.find(vstr[i]) != ss.end()) {
i++;
continue;
}
cout << vstr[i] << endl;
f = 0;
ss.insert(vstr[i]);
i += n;
}
if (f) cout << "Keep going..." << endl;
system("pause");
return 0;
}