Every morning she will ask the mirror: 'Mirror mirror tell me, who is the most beautiful girl in the world?' If the mirror says her name, she will praise the mirror: 'Good guy!', but if the mirror says the name of another person, she will assail the mirror: 'Dare you say that again?'

Today Jessie asks the mirror the same question above, and you are given a series of mirror's answers. For each answer, please output Jessie's response. You can assume that the uppercase or lowercase letters appearing anywhere in the name will have no influence on the answer. For example, 'Jessie' and 'jessie' represent the same person.

Input

The first line contains an integer T(1 \le T \le 100)T(1≤T≤100), which is the number of test cases.

Each test case contains one line with a single-word name, which contains only English letters. The length of each name is no more than 1515.

Output

For each test case, output one line containing the answer.

樣例輸入複製

2
Jessie
Justin

樣例輸出複製

Good guy!
Dare you say that again?

題目來源

題目意思是，給你一個字串，不區分大小寫，如果等於“jessie”，就輸出“Good guy!”，反之就輸出“Dare you say that again?”

#include<iostream>
#include<cstring>
using namespace std;

int main()
{
	char a[100];
	int n,m,j,k,i,T;
	cin>>T;
	getchar();
	while (T--)
	{
		scanf("%s",a);
	int len=strlen(a);
	for (i=0;i<len;i++)
	{
		if (a[i]>='A'&&a[i]<='Z')
		a[i] = a[i]-'A'+'a';
	}
	if (strcmp(a,"jessie")==0)
		
		cout<<"Good guy!"<<endl;
		else
		cout<<"Dare you say that again?"<<endl;
	}
	
	
	return 0;
}