[LeetCode] 227. Basic Calculator II
阿新 • • 發佈:2018-12-10
Problem
Implement a basic calculator to evaluate a simple expression string.
The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero.
Example 1:
Input: "3+2*2"
Output: 7
Example 2:
Input: " 3/2 "
Output: 1
Example 3:
Input: " 3+5 / 2 "
Output: 5
Note:
You may assume that the given expression is always valid.Do not use the eval built-in library function.
Solution
class Solution { public int calculate(String s) { s = s.trim().replaceAll(" ", ""); if (s == null || s.length() == 0) return 0; int res = 0; long pre = 0; char sign = '+'; int i = 0; while (i < s.length()) { long cur = 0; while (i < s.length() && Character.isDigit(s.charAt(i))) { cur = cur*10 + (s.charAt(i)-'0'); i++; } switch (sign) { case '+': res += pre; pre = cur; break; case '-': res += pre; pre = -cur; break; case '*': pre *= cur; break; case '/': pre /= cur; break; } if (i < s.length()) { sign = s.charAt(i); i++; } } res += pre; return res; } }