java 對json的處理,主流json jar 包轉換方式
主流Java json 庫的實現分析: https://blog.csdn.net/u013063153/article/details/73163624
1.fastjson
主要處理物件是JSON,通過JSON.toJSONString(obj) 來將資料轉為json 格式,通過 JSON.parseObject 將資料轉換為所需格式
其他型別轉為json 型別的String
String json = JSON.toJSONString(model); // serializes model to Json
jsonString 轉其他型別
Model model2 = JSON.parseObject(json, Model.class); // deserializes json into model2
其他型別轉jsonObject
JSONObject jb = JSON.parseObject(String text);
2.gson
主要處理物件是Gson ,通過Gson.toJson(obj) 轉為json 格式 ,通過Gson.fromJson 轉換為所需的java物件
String 型別轉 gson, gson 轉其他型別
Gson gson = new Gson();
String json = gson.toJson(str);
System.out.println(json);
String fromJson = gson.fromJson(json, String.class);
System.out.println(fromJson);
json 轉 map
Map<String,Object> map = new Gson().fromJson(urlGetToQualifiedPath, new TypeToken<HashMap<String,Object>>(){}.getType());//gson
3.json-lib
JSONObject fromObject = JSONObject.fromObject(JsonMessage.str);
System.out.println(fromObject);
String bean = (String) JSONObject.toBean(fromObject, String.class);
System.out.println(bean);
4.jackson
主要是ObjectMapper物件
json 轉 map
String responseMessageGet = TestOKHttp.getResponseMessageGet(url);
ObjectMapper mapper = new ObjectMapper();
Map<String,String> reMap = null;
reMap = mapper.readValue(responseMessageGet, new TypeReference<Map<String,Object>>(){});
map 轉 json
ObjectMapper mapper = new ObjectMapper();
String jsonReturn = null;
jsonReturn = mapper.writeValueAsString(map);