1. 程式人生 > >Leetcode 103. Binary Tree Zigzag Level Order Traversal

Leetcode 103. Binary Tree Zigzag Level Order Traversal

文章作者:Tyan 部落格:noahsnail.com  |  CSDN  |  簡書

1. Description

Binary Tree Zigzag Level Order Traversal

2. Solution

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    vector<
vector<int>> zigzagLevelOrder(TreeNode* root) { vector<vector<int>> result; zigzagTraverse(result, root, 0); for(int i = 0; i < result.size(); i++) { if(i % 2 == 1) { reverse(result[i].begin(), result[i].end()); } }
return result; } private: void zigzagTraverse(vector<vector<int>>& result, TreeNode* root, int depth) { if(!root) { return; } depth++; if(depth > result.size()) { vector<int> values; result.
emplace_back(values); } result[depth - 1].push_back(root->val); zigzagTraverse(result, root->left, depth); zigzagTraverse(result, root->right, depth); } };

Reference