Base:階乘+九九乘法表
阿新 • • 發佈:2018-12-11
階乘:
例如:
2的階乘:1x2
4的階乘:1x2x3x4
package com.wochat.controller; public class MainClass { public static void main(String[] args) { long sum = 1; int score = 10; for (int i = 1; i <= score; i++) { sum *= i; } System.out.println(sum); } }
10的階乘:3628800
如果,求100的階乘:93326215443944152681699238856266700490715968264381621468592963895217599993229915608941463976156518286253697920827223758251185210916864000000000000000000000000
其值超出long的範圍
import java.math.BigInteger; int s=100; BigInteger a=new BigInteger("1"); for (int i = 1; i <=s; i++) { BigInteger b=new BigInteger(String.valueOf(i)); a=a.multiply(b); } System.out.println(a);
String s="93326215443944152681699238856266700490715968264381621468592963895217599993229915608941463976156518286253697920827223758251185210916864000000000000000000000000";
System.out.println(s.length());
100的階乘是158位
當然,在階乘這種問題下,遞迴是最裝B的
無形的裝叉最致命!
package com.wochat.controller; public class MainClass { public static void main(String[] args) { System.out.println(vsum(10)); } public static int vsum(int v){ int sum; if (v<=1){ sum=v; } else{ sum=v*vsum(v-1); } return sum; } }
改動一下:
package com.wochat.controller;
public class MainClass {
public static void main(String[] args) {
System.out.println(vsum(-1));
}
public static int vsum(int v) {
if (v <= 1) {
return v;
} else {
return v * vsum(v - 1);
}
}
}
最為簡單的九九乘法表
for (int i = 1; i <= 9; i++) {
for (int j = 1; j <=9; j++) {
System.out.print(i+"x"+j+"="+i*j+"\t");
}
System.out.println();
}
1x1=1
2x1=2 2x2=4
3x1=3 3x2=6 3x3=9
4x1=4 4x2=8 4x3=12 4x4=16
5x1=5 5x2=10 5x3=15 5x4=20 5x5=25
6x1=6 6x2=12 6x3=18 6x4=24 6x5=30 6x6=36
7x1=7 7x2=14 7x3=21 7x4=28 7x5=35 7x6=42 7x7=49
8x1=8 8x2=16 8x3=24 8x4=32 8x5=40 8x6=48 8x7=56 8x8=64
9x1=9 9x2=18 9x3=27 9x4=36 9x5=45 9x6=54 9x7=63 9x8=72 9x9=81
for (int i = 1; i <= 9; i++) {
for (int j = 1; j <=i; j++) {
System.out.print(i+"x"+j+"="+i*j+"\t");
}
System.out.println();
}
對比一下兩段程式碼,改動一下啊,就有不同的效果
這就是Java的神奇之處!