leetcode 448 Find All Numbers Disappeared in an Array
class Solution { public List<Integer> findDisappearedNumbers(int[] nums) { int n = nums.length; ArrayList<Integer> ans = new ArrayList<Integer>(); boolean[] vis = new boolean[n+1]; for(int i=0;i<n;i++){ vis[nums[i]] = true; } for(int i=1;i<=n;i++){ if(!vis[i]) ans.add(i); } return ans; } }
時間復雜度O(n),空間復雜度O(n)。空間復雜度O(1)的不會做- -待補
leetcode 448 Find All Numbers Disappeared in an Array
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red res cat leet pub ear index 意思 ++ 這兩道題很有意思,由於元素為1~n,因此每個元素的值-1(映射到0~n-1)就可以直接當做下標。這樣將 nums 中對應下標的元素 *-1 以i表示 index+1 這個元素出現過了,能節省存儲的空間
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