Python 用棧判斷括號匹配
阿新 • • 發佈:2018-12-13
#!/usr/bin/python # -*- coding: UTF-8 -*-
from pythonds.basic.stack import Stack
def parChecker(symbolString): s = Stack() balanced = True index = 0 while index < len(symbolString) and balanced: symbol =symbolString[index]
#左邊括號入棧 if symbol == '(': s.push(symbol)else:
#如果棧提前為空,則表示前面匹配成功,後面沒有匹配成功 if s.isEmpty(): balanced = False
#右邊括號出棧 else: s.pop()
index += 1
if balanced and s.isEmpty(): return True else: return False print(parChecker('()())'))print(parChecker('()()()')) print(parChecker('((()())())'))